Subjects agricultural engineering

Combine Capacity 88329D

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1. **Problem statement:** Calculate the field capacity, material capacity, and throughput capacity of a combine harvester given: - Width of cut $= 5$ m - Speed $= 1.5$ m/s - Grain collected in 1 minute $= 50$ kg - Material discharged in 1 minute $= 60$ kg 2. **Formulas and explanations:** - Field capacity (FC) is the area harvested per unit time, calculated as: $$\text{FC} = \text{width} \times \text{speed}$$ This gives area per second; convert to hectares per hour (ha/h) for practical use. - Material capacity (MC) is the mass of material harvested per unit time. - Throughput capacity (TC) is the total mass processed per unit time (grain + discharged material). 3. **Calculate field capacity:** - Width $= 5$ m - Speed $= 1.5$ m/s - Area per second $= 5 \times 1.5 = 7.5$ m$^2$/s - Convert to hectares per hour: $$7.5 \text{ m}^2/\text{s} \times \frac{3600 \text{ s}}{1 \text{ h}} = 27000 \text{ m}^2/\text{h}$$ $$27000 \text{ m}^2/\text{h} = 2.7 \text{ ha/h}$$ 4. **Calculate material capacity:** - Grain collected in 1 minute $= 50$ kg - Convert to per hour: $$50 \text{ kg/min} \times 60 = 3000 \text{ kg/h}$$ 5. **Calculate throughput capacity:** - Total material per minute $= 50 + 60 = 110$ kg - Convert to per hour: $$110 \text{ kg/min} \times 60 = 6600 \text{ kg/h}$$ **Final answers:** - Field capacity $= 2.7$ ha/h - Material capacity $= 3000$ kg/h - Throughput capacity $= 6600$ kg/h