1. **Find theoretical machine capacity for a 3 m mower** Theoretical machine capacity (ha/h) is calculated by the formula: $$\text{Theoretical Capacity} = \frac{\text{Width of cut (m)} \times \text{Speed (m/s)}}{10,000} \times 3600$$ - Width of cut = 3 m - Distance traveled = 100 m - Time taken = 52 s Calculate speed: $$\text{Speed} = \frac{100}{52} \approx 1.923 \, m/s$$ Calculate capacity: $$\text{Capacity} = \frac{3 \times 1.923}{10,000} \times 3600 = \frac{5.769}{10,000} \times 3600 = 0.5769 \times 3.6 = 2.0768 \, ha/h$$ 2. **Find actual field capacity for a 2 m mower** Actual field capacity is given by: $$\text{Actual Capacity} = \text{Width (m)} \times \text{Speed (km/h)} \times \text{Field Efficiency} / 10$$ - Width = 2 m - Speed = 8 km/h - Field efficiency = 0.80 Calculate: $$\text{Actual Capacity} = \frac{2 \times 8 \times 0.80}{10} = \frac{12.8}{10} = 1.28 \, ha/h$$ 3. **Determine field capacity of 4 m combine in soybeans** Effective width is row spacing times number of rows covered. Since rows are 70 cm (0.7 m), and width is 4 m, the effective width is 4 m (already given as width of cut). Use the same formula as above: - Width = 4 m - Speed = 4.5 km/h - Field efficiency = 0.70 Calculate: $$\text{Field Capacity} = \frac{4 \times 4.5 \times 0.70}{10} = \frac{12.6}{10} = 1.26 \, ha/h$$ **Final answers:** 1. Theoretical capacity for 3 m mower = $2.08$ ha/h 2. Actual field capacity for 2 m mower = $1.28$ ha/h 3. Field capacity for 4 m combine = $1.26$ ha/h