Subjects algebra and geometry

Sum And Shapes D4F625

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1. The problem involves understanding the formula for the sum of the first $n$ natural numbers and the value of $\pi$. 2. The formula given is $$\sum_{k=1}^n k = \frac{n(n + 1)}{2}$$ which means the sum of all integers from 1 to $n$ equals $\frac{n(n + 1)}{2}$. 3. This formula is derived from pairing numbers in the sequence: the first and last, second and second last, and so on, each pair summing to $n+1$. 4. For example, if $n=5$, the sum is $$\frac{5(5+1)}{2} = \frac{5 \times 6}{2} = 15$$. 5. The value of $\pi$ is approximately 3.1415926535, which is a constant used in calculations involving circles. 6. The problem also mentions shapes: a blue circle centered at $(1,1)$ with radius 1, and a red ellipse centered at $(2,2)$ with radii 1.5 and 0.5. 7. The circle equation is $$(x-1)^2 + (y-1)^2 = 1^2 = 1$$. 8. The ellipse equation is $$\frac{(x-2)^2}{1.5^2} + \frac{(y-2)^2}{0.5^2} = 1$$. These equations describe the shapes mentioned. Final answers: - Sum formula: $$\sum_{k=1}^n k = \frac{n(n + 1)}{2}$$ - Circle equation: $$(x-1)^2 + (y-1)^2 = 1$$ - Ellipse equation: $$\frac{(x-2)^2}{2.25} + \frac{(y-2)^2}{0.25} = 1$$