1. **State the problem:** Solve the inequality $|x-2| > 5$.
2. **Recall the definition of absolute value inequality:** For $|A| > B$ where $B > 0$, the solution is $A < -B$ or $A > B$.
3. **Apply the rule:** Here, $A = x-2$ and $B = 5$, so
$$x - 2 < -5 \quad \text{or} \quad x - 2 > 5$$
4. **Solve each inequality separately:**
- For $x - 2 < -5$:
$$x < -5 + 2$$
$$x < -3$$
- For $x - 2 > 5$:
$$x > 5 + 2$$
$$x > 7$$
5. **Write the final solution:**
$$x < -3 \quad \text{or} \quad x > 7$$
This means $x$ is any number less than $-3$ or greater than $7$.
Absolute Inequality 1D387C
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