1. **State the problem:** Solve the inequality $$|x - 6| < 7$$ algebraically.
2. **Recall the rule for absolute value inequalities:** For any real number $a$ and positive number $b$, $$|a| < b \iff -b < a < b$$.
3. **Apply the rule:** Here, $a = x - 6$ and $b = 7$, so
$$-7 < x - 6 < 7$$.
4. **Solve the compound inequality:** Add 6 to all parts:
$$-7 + 6 < x - 6 + 6 < 7 + 6$$
5. **Show cancellation step:**
$$-7 + 6 < \cancel{x - 6} + 6 < 7 + 6$$
6. **Simplify:**
$$-1 < x < 13$$
7. **Final answer:** The solution set is all real numbers $x$ such that $$-1 < x < 13$$.
This means $x$ lies strictly between $-1$ and $13$.
Absolute Inequality 7Ff4D7
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