1. **State the problem:** Solve the inequality $$2|2x - 1| + 2 > 4$$.
2. **Isolate the absolute value expression:** Subtract 2 from both sides:
$$2|2x - 1| > 2$$
3. **Divide both sides by 2:**
$$|2x - 1| > 1$$
4. **Recall the definition of absolute value inequality:** For $$|A| > B$$ where $$B > 0$$, the solution is $$A < -B$$ or $$A > B$$.
5. **Apply this to our inequality:**
$$2x - 1 < -1 \quad \text{or} \quad 2x - 1 > 1$$
6. **Solve each inequality separately:**
- For $$2x - 1 < -1$$:
$$2x < 0$$
$$x < 0$$
- For $$2x - 1 > 1$$:
$$2x > 2$$
$$x > 1$$
7. **Combine the solution sets:**
$$x < 0 \quad \text{or} \quad x > 1$$
8. **Write the solution in interval notation:**
$$(-\infty, 0) \cup (1, \infty)$$
**Final answer:** The solution set is $$(-\infty, 0) \cup (1, \infty)$$.
Absolute Inequality D8Ff64
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