1. **State the problem:**
We are given a V-shaped absolute value graph with vertex at $(-4, 2)$ opening upwards. We need to find the equation of the function in the form $a|x - h| + k$ where $a$, $h$, and $k$ are integers or simplified fractions.
2. **Recall the formula:**
The general form of an absolute value function is:
$$y = a|x - h| + k$$
where $(h, k)$ is the vertex and $a$ controls the slope (steepness) and direction (up or down).
3. **Identify vertex:**
From the graph, vertex is at $(-4, 2)$, so $h = -4$ and $k = 2$.
4. **Find $a$ using another point:**
Choose a point on the graph other than the vertex. For example, the point $(0, 6)$ lies on the graph.
5. **Plug values into the formula:**
$$6 = a|0 - (-4)| + 2$$
$$6 = a|4| + 2$$
$$6 = 4a + 2$$
6. **Solve for $a$:**
$$6 - 2 = 4a$$
$$4 = 4a$$
$$a = \frac{4}{4} = 1$$
7. **Write the final equation:**
$$y = 1|x - (-4)| + 2 = |x + 4| + 2$$
**Answer:**
$$y = |x + 4| + 2$$
Absolute Value 1F159F
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