1. The problem is to simplify the expression $A=3|1-2x|-5$. 2. The absolute value function $|y|$ returns the distance of $y$ from zero, so it is always non-negative. 3. The expression inside the absolute value is $1-2x$. 4. The expression $3|1-2x|-5$ means multiply the absolute value of $1-2x$ by 3, then subtract 5. 5. To simplify, we keep the absolute value as is since it depends on $x$ and cannot be simplified further without knowing $x$. 6. Therefore, the simplified form is $A=3|1-2x|-5$. 7. This expression is already in its simplest form unless you want to consider cases for $x$ where $1-2x$ is positive or negative. Final answer: $A=3|1-2x|-5$