1. **State the problem:** Solve the system of equations:
$$y = |x|$$
$$y = 2|x| + 3$$
2. **Set the equations equal to find intersection points:**
Since both equal $y$, set:
$$|x| = 2|x| + 3$$
3. **Solve for $|x|$:**
$$|x| = 2|x| + 3$$
Subtract $2|x|$ from both sides:
$$|x| - 2|x| = 3$$
$$\cancel{|x|} - 2\cancel{|x|} = 3$$
$$- |x| = 3$$
Multiply both sides by $-1$:
$$|x| = -3$$
4. **Analyze the result:**
The absolute value $|x|$ cannot be negative, so $|x| = -3$ has no solution.
5. **Conclusion:**
There is no $x$ that satisfies both equations simultaneously.
**Final answer:** No solution.
Absolute Value System A9F7Cb
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