1. **Problem:** Find the value of $\frac{5}{6} - \frac{1}{3}$.
2. **Formula and rules:** To subtract fractions, they must have a common denominator.
3. **Step 1:** Find the least common denominator (LCD) of 6 and 3, which is 6.
4. **Step 2:** Convert $\frac{1}{3}$ to an equivalent fraction with denominator 6:
$$\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}$$
5. **Step 3:** Subtract the fractions:
$$\frac{5}{6} - \frac{2}{6} = \frac{5 - 2}{6} = \frac{3}{6}$$
6. **Step 4:** Simplify the fraction by dividing numerator and denominator by their greatest common divisor (3):
$$\frac{\cancel{3}}{\cancel{6}} = \frac{1}{2}$$
7. **Answer:** $\frac{5}{6} - \frac{1}{3} = \frac{1}{2}$.
---
1. **Problem:** Find the value of $\frac{3}{4} + \frac{1}{2} \times \frac{4}{6}$.
2. **Formula and rules:** Follow order of operations: multiply before adding.
3. **Step 1:** Multiply $\frac{1}{2} \times \frac{4}{6}$:
$$\frac{1}{2} \times \frac{4}{6} = \frac{1 \times 4}{2 \times 6} = \frac{4}{12}$$
4. **Step 2:** Simplify $\frac{4}{12}$ by dividing numerator and denominator by 4:
$$\frac{\cancel{4}}{\cancel{12}} = \frac{1}{3}$$
5. **Step 3:** Add $\frac{3}{4} + \frac{1}{3}$.
6. **Step 4:** Find the least common denominator (LCD) of 4 and 3, which is 12.
7. **Step 5:** Convert both fractions to have denominator 12:
$$\frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12}$$
$$\frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12}$$
8. **Step 6:** Add the fractions:
$$\frac{9}{12} + \frac{4}{12} = \frac{9 + 4}{12} = \frac{13}{12}$$
9. **Step 7:** Express as a mixed number:
$$\frac{13}{12} = 1 \frac{1}{12}$$
10. **Answer:** $\frac{3}{4} + \frac{1}{2} \times \frac{4}{6} = 1 \frac{1}{12}$.
Add Subtract Fractions 96B834
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.