1. The problem is to complete the addition pyramid where each number above is the sum of the two numbers directly below it. 2. The bottom row has three fractions: $\frac{1}{4}$, $\frac{1}{8}$, and $\frac{1}{3}$. 3. Calculate the two numbers in the middle row: - Left middle box: $\frac{1}{4} + \frac{1}{8} = \frac{2}{8} + \frac{1}{8} = \frac{3}{8}$ - Right middle box: $\frac{1}{8} + \frac{1}{3} = \frac{3}{24} + \frac{8}{24} = \frac{11}{24}$ 4. The top box is the sum of the two middle boxes: $$\frac{3}{8} + \frac{11}{24} = \frac{9}{24} + \frac{11}{24} = \frac{20}{24} = \frac{5}{6}$$ 5. The problem states the top box is 1, but our calculation shows $\frac{5}{6}$. This suggests the top box should be $\frac{5}{6}$ to be consistent with the sums. Final completed pyramid: Bottom row: $\frac{1}{4}$, $\frac{1}{8}$, $\frac{1}{3}$ Middle row: $\frac{3}{8}$, $\frac{11}{24}$ Top row: $\frac{5}{6}$