1. **Problem statement:** Suppose two siblings currently have ages in the ratio 3:5. Years ago, the ratio of their ages was half the ratio of their ages years from now. Find their current ages.
2. **Define variables:** Let the current ages be $3x$ and $5x$.
3. **Set up expressions for ages years ago and years from now:**
- Years ago, their ages were $3x - y$ and $5x - y$.
- Years from now, their ages will be $3x + y$ and $5x + y$.
4. **Write the ratio condition:**
The ratio years ago is half the ratio years from now:
$$\frac{3x - y}{5x - y} = \frac{1}{2} \times \frac{3x + y}{5x + y}$$
5. **Cross multiply to clear fractions:**
$$2(3x - y)(5x + y) = (5x - y)(3x + y)$$
6. **Expand both sides:**
Left: $2[(3x)(5x) + (3x)(y) - y(5x) - y(y)] = 2(15x^2 + 3xy - 5xy - y^2) = 2(15x^2 - 2xy - y^2) = 30x^2 - 4xy - 2y^2$
Right: $(5x)(3x) + (5x)(y) - y(3x) - y(y) = 15x^2 + 5xy - 3xy - y^2 = 15x^2 + 2xy - y^2$
7. **Set equation:**
$$30x^2 - 4xy - 2y^2 = 15x^2 + 2xy - y^2$$
8. **Bring all terms to one side:**
$$30x^2 - 4xy - 2y^2 - 15x^2 - 2xy + y^2 = 0$$
Simplify:
$$15x^2 - 6xy - y^2 = 0$$
9. **Rewrite as:**
$$15x^2 - 6xy - y^2 = 0$$
10. **Solve for $y$ in terms of $x$:** Treat as quadratic in $y$:
$$-y^2 - 6xy + 15x^2 = 0$$
Multiply both sides by $-1$:
$$y^2 + 6xy - 15x^2 = 0$$
11. **Use quadratic formula:**
$$y = \frac{-6x \pm \sqrt{(6x)^2 - 4(1)(-15x^2)}}{2} = \frac{-6x \pm \sqrt{36x^2 + 60x^2}}{2} = \frac{-6x \pm \sqrt{96x^2}}{2}$$
12. **Simplify square root:**
$$\sqrt{96x^2} = x\sqrt{96} = x \times 4\sqrt{6}$$
13. **So:**
$$y = \frac{-6x \pm 4x\sqrt{6}}{2} = x \frac{-6 \pm 4\sqrt{6}}{2} = x(-3 \pm 2\sqrt{6})$$
14. **Since $y$ is a positive number of years, choose positive root:**
$$y = x(-3 + 2\sqrt{6})$$
15. **Find current ages:**
- First sibling: $3x$
- Second sibling: $5x$
16. **Example:** Let $x=1$ for simplicity:
- $y = -3 + 2\sqrt{6} \approx -3 + 4.89898 = 1.89898$
- Ages years ago: $3 - 1.89898 = 1.10102$, $5 - 1.89898 = 3.10102$
- Ages years from now: $3 + 1.89898 = 4.89898$, $5 + 1.89898 = 6.89898$
17. **Check ratio condition:**
- Ratio years ago: $\frac{1.10102}{3.10102} \approx 0.355
- Ratio years from now: $\frac{4.89898}{6.89898} \approx 0.710$
- Half of ratio years from now: $0.710 / 2 = 0.355$
18. **Answer:** The current ages are $3x$ and $5x$ where $y = x(-3 + 2\sqrt{6})$ years satisfies the condition. For example, if $x=1$, ages are 3 and 5 years, and $y \approx 1.9$ years.
Age Ratio Problem 7B3D88
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