1. **State the problem:** Meya and Eric's combined ages equal Sam's age, which is 69 years. Meya is twice Eric's age. 2. **Define variables:** Let $m$ = Meya's age Let $e$ = Eric's age 3. **Write the relationships as equations:** From the problem, we have: $$m + e = 69$$ and $$m = 2e$$ 4. **Substitute $m = 2e$ into the first equation:** $$2e + e = 69$$ 5. **Simplify the equation:** $$3e = 69$$ 6. **Solve for $e$:** $$e = \frac{69}{3}$$ $$e = 23$$ 7. **Find $m$ using $m = 2e$:** $$m = 2 \times 23$$ $$m = 46$$ 8. **Answer:** Meya's age is $46$ years. Eric's age is $23$ years. 9. **Check:** Sum of ages: $46 + 23 = 69$, which matches Sam's age. Thus, the equation representing the relationship is: $$m + e = 69$$ with $$m = 2e$$