1. **State the problem:** Farmer Gespil starts with 86 alabers and gains 8 alabers every hour. We want to write an equation for the total alabers $y$ after $x$ hours, find how many alabers she has after 10 hours, and find how many hours it takes to have 230 alabers. 2. **Write the equation in slope-intercept form:** The slope-intercept form is $$y = mx + b$$ where $m$ is the rate of change (slope) and $b$ is the initial value (y-intercept). Here, $m = 8$ alabers/hour and $b = 86$ alabers. So, the equation is: $$y = 8x + 86$$ 3. **Calculate alabers after 10 hours:** Substitute $x = 10$ into the equation: $$y = 8(10) + 86 = 80 + 86 = 166$$ Farmer Gespil will have 166 alabers after 10 hours. 4. **Find hours to have 230 alabers:** Set $y = 230$ and solve for $x$: $$230 = 8x + 86$$ Subtract 86 from both sides: $$230 - 86 = 8x$$ $$144 = 8x$$ Divide both sides by 8: $$\cancel{8}x = \frac{144}{\cancel{8}}$$ $$x = 18$$ It will take 18 hours to have 230 alabers. 5. **Summary:** - Equation: $$y = 8x + 86$$ - Alabers after 10 hours: 166 - Hours to reach 230 alabers: 18