Subjects algebra

Algebra Expressions 6Bdcb7

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1. **State the problem:** We are given variables $a=3$, $b=4$, $c=\frac{1}{2}$, and $d=100$. We need to solve the following expressions: - $\frac{ab}{d}$ - $(d + b) - ac$ - $5(d - b)$ - $c^a$ 2. **Solve $\frac{ab}{d}$:** Calculate numerator $ab = 3 \times 4 = 12$. Write the fraction: $$\frac{ab}{d} = \frac{12}{100}$$ Simplify the fraction by dividing numerator and denominator by 4: $$\frac{\cancel{12}^{3}}{\cancel{100}^{25}} = \frac{3}{25}$$ Convert to decimal: $$\frac{3}{25} = 0.12$$ 3. **Solve $(d + b) - ac$:** Calculate $d + b = 100 + 4 = 104$. Calculate $ac = 3 \times \frac{1}{2} = \frac{3}{2} = 1.5$. Substitute: $$(d + b) - ac = 104 - 1.5 = 102.5$$ 4. **Solve $5(d - b)$:** Calculate $d - b = 100 - 4 = 96$. Multiply by 5: $$5 \times 96 = 480$$ 5. **Solve $c^a$:** Calculate $c^a = \left(\frac{1}{2}\right)^3 = \frac{1^3}{2^3} = \frac{1}{8} = 0.125$ **Final answers:** - $\frac{ab}{d} = 0.12$ - $(d + b) - ac = 102.5$ - $5(d - b) = 480$ - $c^a = 0.125$