1. **Problem 1: List subsets of the set \{4, 5, 6\}**
The subsets of a set include the empty set, single-element sets, two-element sets, and the full set itself.
2. **Subsets of \{4, 5, 6\}:**
- \{\}\ (empty set)
- \{4\}, \{5\}, \{6\}
- \{4, 5\}, \{4, 6\}, \{5, 6\}
- \{4, 5, 6\}
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3. **Problem 2: Graph the inequality \(y > -\frac{1}{3}x - 2\)**
- The boundary line is \(y = -\frac{1}{3}x - 2\).
- The slope is \(-\frac{1}{3}\), and the y-intercept is \(-2\).
- The inequality \(y > -\frac{1}{3}x - 2\) means the region above this line is shaded.
4. **Check if point \((0, 3)\) fits the inequality:**
Substitute \(x=0\) and \(y=3\):
$$3 > -\frac{1}{3} \times 0 - 2 = -2$$
Since \(3 > -2\) is true, the point \((0, 3)\) satisfies the inequality.
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5. **Problem 3: Match lines and rotate 90° around (0,0)**
- Original lines:
- \(y = 3x\) (line with slope 3)
- \(y = 3\) (horizontal line)
- \(x = 3\) (vertical line)
6. **Rotate \(y = 3x\) by 90° around (0,0):**
- The slope of the original line is \(m = 3\).
- The slope of the rotated line is \(m' = -\frac{1}{m} = -\frac{1}{3}\) (negative reciprocal).
- The rotated line passes through (0,0), so its equation is:
$$y = -\frac{1}{3}x$$
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7. **Problem 4: Slope and translation of line through points (-2,5) and (4,2)**
- Slope formula:
$$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 5}{4 - (-2)} = \frac{-3}{6} = -\frac{1}{2}$$
- Equation of the line in point-slope form using point (-2,5):
$$y - 5 = -\frac{1}{2}(x + 2)$$
- Simplify:
$$y - 5 = -\frac{1}{2}x - 1$$
$$y = -\frac{1}{2}x - 1 + 5$$
$$y = -\frac{1}{2}x + 4$$
- Translate the line up by 5 units:
$$y_{new} = y + 5 = -\frac{1}{2}x + 4 + 5 = -\frac{1}{2}x + 9$$
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**Summary:**
- Subsets of \{4,5,6\} listed.
- Graph and inequality \(y > -\frac{1}{3}x - 2\) explained.
- Point (0,3) satisfies the inequality.
- Rotation of line \(y=3x\) by 90° is \(y = -\frac{1}{3}x\).
- Slope of line through (-2,5) and (4,2) is \(-\frac{1}{2}\).
- New equation after translation up 5 units is \(y = -\frac{1}{2}x + 9\).
Algebra Inequalities 9Af0Af
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