1. Let's start by stating the problem: We want to describe the algebraic equation $10x - 49 = 51$ using a real-life situation.
2. The equation $10x - 49 = 51$ means that if you take 10 times a number $x$ and subtract 49, you get 51.
3. A common real-life example could be: Imagine you have $x$ boxes, each containing 10 candies. You gave away 49 candies, and now you have 51 candies left.
4. The equation models this situation: Total candies initially = $10x$, candies given away = 49, candies left = 51.
5. To find how many boxes $x$ you had, solve the equation:
$$10x - 49 = 51$$
6. Add 49 to both sides:
$$10x - \cancel{49} + 49 = 51 + 49$$
$$10x = 100$$
7. Divide both sides by 10:
$$\frac{10x}{\cancel{10}} = \frac{100}{10}$$
$$x = 10$$
8. So, you had 10 boxes of candies initially.
This example shows how algebraic expressions can represent real-world situations involving quantities, changes, and totals.
Algebra Real Life 4C7Efc
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