Subjects algebra

Algebra Simplification Cfbb6A

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Question: D 2(2m - n) 3(2m + n) 16 Simplify 3/7b(14a - 21b) - a/2b. A 11a + 18b 2b B 11a - 18b 2b C 12a - 17b 2b D 13a - 18b 2b top-right: a multiple-choice algebra simplification problem is shown, with the expression 3/7b(14a - 21b) - a/2b and answer options A, B, C, D arranged vertically.User: Help. Form 2 maths.
1. **State the problem:** Simplify the expression $$\frac{3}{7b}(14a - 21b) - \frac{a}{2b}$$ and match it to one of the given options. 2. **Recall the distributive property:** $$k(x - y) = kx - ky$$ and rules for fractions. 3. **Distribute $$\frac{3}{7b}$$ over $$14a - 21b$$:** $$\frac{3}{7b} \times 14a - \frac{3}{7b} \times 21b$$ 4. **Calculate each term:** $$\frac{3 \times 14a}{7b} - \frac{3 \times 21b}{7b} = \frac{42a}{7b} - \frac{63b}{7b}$$ 5. **Simplify each fraction:** $$\frac{42a}{7b} = \frac{\cancel{7}6a}{\cancel{7}b} = \frac{6a}{b}$$ $$\frac{63b}{7b} = \frac{\cancel{7}9\cancel{b}}{\cancel{7}\cancel{b}} = 9$$ 6. **Rewrite the expression:** $$\frac{6a}{b} - 9 - \frac{a}{2b}$$ 7. **Combine the fractional terms $$\frac{6a}{b}$$ and $$-\frac{a}{2b}$$:** Find common denominator $$2b$$: $$\frac{6a}{b} = \frac{6a \times 2}{b \times 2} = \frac{12a}{2b}$$ So, $$\frac{12a}{2b} - \frac{a}{2b} = \frac{12a - a}{2b} = \frac{11a}{2b}$$ 8. **Rewrite the expression including the constant term:** $$\frac{11a}{2b} - 9$$ 9. **Express $$9$$ with denominator $$2b$$ to combine:** $$9 = \frac{18b}{2b}$$ 10. **Final subtraction:** $$\frac{11a}{2b} - \frac{18b}{2b} = \frac{11a - 18b}{2b}$$ 11. **Match with options:** This matches option B: $$\frac{11a - 18b}{2b}$$. **Final answer:** Option B.