1. The problem asks to find the antilogarithm of 2.5620. 2. The antilogarithm (or inverse logarithm) of a number $x$ is given by $10^x$ when the logarithm base is 10. 3. So, the antilogarithm of 2.5620 is calculated as: $$10^{2.5620}$$ 4. To evaluate this, we can rewrite it as: $$10^{2 + 0.5620} = 10^2 \times 10^{0.5620}$$ 5. We know $10^2 = 100$. 6. Now, calculate $10^{0.5620}$. Using a calculator or logarithm tables, $10^{0.5620} \approx 3.64$. 7. Multiply these results: $$100 \times 3.64 = 364$$ 8. Therefore, the antilogarithm of 2.5620 is approximately 364. 9. The figure most likely representing the antilogarithm of 2.5620 is the one showing a value near 364.