1. **State the problem:** We are given an arithmetic progression (AP) with the first three terms as $-2, -4, -6$. We need to find the 10th term of this AP. 2. **Recall the formula for the $n$th term of an AP:** $$a_n = a_1 + (n-1)d$$ where $a_n$ is the $n$th term, $a_1$ is the first term, $d$ is the common difference, and $n$ is the term number. 3. **Find the common difference $d$:** $$d = a_2 - a_1 = -4 - (-2) = -4 + 2 = -2$$ 4. **Use the formula to find the 10th term:** $$a_{10} = a_1 + (10-1)d = -2 + 9 \times (-2)$$ 5. **Calculate:** $$a_{10} = -2 - 18 = -20$$ **Final answer:** The 10th term of the AP is $-20$.