1. **Problem:** In an arithmetic progression (AP), given $a_1 = 7$ and common difference $d = 3$, find the 10th term $a_{10}$.
2. **Formula:** The $n$th term of an AP is given by:
$$a_n = a_1 + (n-1)d$$
3. **Substitute values:**
$$a_{10} = 7 + (10-1) \times 3$$
4. **Calculate:**
$$a_{10} = 7 + 9 \times 3 = 7 + 27 = 34$$
5. **Answer:** The 10th term $a_{10}$ is 34.
Ap Term 402Dbf
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