Subjects algebra

Apple Cost 9B85Ab

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1. **State the problem:** Magda buys 6 apples and 4 oranges for a total cost of 4.18. Each orange costs 0.52. We need to find the cost of one apple. 2. **Define variables:** Let the cost of one apple be $x$. 3. **Write the equation:** Total cost = cost of apples + cost of oranges $$6x + 4 \times 0.52 = 4.18$$ 4. **Calculate the total cost of oranges:** $$4 \times 0.52 = 2.08$$ 5. **Substitute back into the equation:** $$6x + 2.08 = 4.18$$ 6. **Isolate $x$:** $$6x = 4.18 - 2.08$$ $$6x = 2.10$$ 7. **Divide both sides by 6:** $$x = \frac{2.10}{6}$$ $$x = \frac{\cancel{2.10}}{\cancel{6}} = 0.35$$ 8. **Answer:** The cost of one apple is $0.35$.