1. **State the problem:**
Jabari needs 575 tickets to get a prize. He already has 210 tickets and earns 31 tickets each time he plays a game. We need to find how many games he must play to have at least 575 tickets.
2. **Set up the equation:**
Let $x$ be the number of games Jabari plays.
Total tickets after playing $x$ games = tickets he already has + tickets earned from playing games
$$210 + 31x \geq 575$$
3. **Solve the inequality:**
Subtract 210 from both sides:
$$\cancel{210} + 31x - \cancel{210} \geq 575 - 210$$
$$31x \geq 365$$
4. **Divide both sides by 31:**
$$\frac{31x}{\cancel{31}} \geq \frac{365}{31}$$
$$x \geq \frac{365}{31}$$
Calculate the division:
$$x \geq 11.77$$
5. **Interpret the result:**
Since Jabari cannot play a fraction of a game, he must play at least 12 games to have enough tickets.
**Final answer:**
Jabari must play **12** games to have enough tickets to win the prize.
Arcade Tickets 504Be4
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