1. **State the problem:** We need to find the first four terms of an arithmetic progression (AP) where the first term $a=2$ and the common difference $d=4$. 2. **Formula for the $n$-th term of an AP:** $$a_n = a + (n-1)d$$ This formula tells us how to find any term in the sequence by knowing the first term and the common difference. 3. **Calculate each term:** - First term: $a_1 = 2 + (1-1) \times 4 = 2 + 0 = 2$ - Second term: $a_2 = 2 + (2-1) \times 4 = 2 + 4 = 6$ - Third term: $a_3 = 2 + (3-1) \times 4 = 2 + 8 = 10$ - Fourth term: $a_4 = 2 + (4-1) \times 4 = 2 + 12 = 14$ 4. **Answer:** The first four terms of the AP are $2, 6, 10, 14$.