1. **State the problem:** We have a sequence starting at 11, and each term is found by subtracting 4 from the previous term. 2. **Formula used:** The nth term of an arithmetic sequence is given by $$a_n = a_1 + (n-1)d$$ where $a_1$ is the first term and $d$ is the common difference. 3. **Given:** - First term $a_1 = 11$ - Common difference $d = -4$ 4. **Find the missing terms:** The sequence given is 11, 7, 3, -1, -5, ... 5. **Calculate the 3rd term:** $$a_3 = 11 + (3-1)(-4) = 11 + 2 \times (-4) = 11 - 8 = 3$$ 6. **Calculate the 4th term:** $$a_4 = 11 + (4-1)(-4) = 11 + 3 \times (-4) = 11 - 12 = -1$$ 7. **Calculate the 5th term:** $$a_5 = 11 + (5-1)(-4) = 11 + 4 \times (-4) = 11 - 16 = -5$$ 8. **Verify the sequence:** 11, 7, 3, -1, -5 **Final answer:** The missing terms are 3, -1, and -5.