1. The problem asks to find the 60th term of the arithmetic sequence 4, -1, -6, ... 2. An arithmetic sequence has a constant difference between consecutive terms. The formula for the $n$th term is: $$a_n = a_1 + (n-1)d$$ where $a_1$ is the first term and $d$ is the common difference. 3. Find the common difference $d$: $$d = a_2 - a_1 = -1 - 4 = -5$$ 4. Use the formula to find the 60th term $a_{60}$: $$a_{60} = 4 + (60-1)(-5)$$ 5. Simplify inside the parentheses: $$a_{60} = 4 + 59 \times (-5)$$ 6. Multiply: $$a_{60} = 4 - 295$$ 7. Calculate the final value: $$a_{60} = -291$$ So, the 60th term of the sequence is $-291$.