1. The problem states that the sequence starts at 12 and each term increases by 6. 2. This is an arithmetic sequence where the first term $a_1 = 12$ and the common difference $d = 6$. 3. The formula for the $n$th term of an arithmetic sequence is: $$a_n = a_1 + (n-1)d$$ 4. To find the 20th term, substitute $n=20$, $a_1=12$, and $d=6$ into the formula: $$a_{20} = 12 + (20-1) \times 6$$ 5. Simplify the expression: $$a_{20} = 12 + 19 \times 6$$ $$a_{20} = 12 + 114$$ $$a_{20} = 126$$ 6. Therefore, the 20th term of the sequence is 126.