1. **State the problem:** We are given the arithmetic sequence defined by the formula $a(n) = -6 - 4(n - 1)$ and need to understand or find terms of this sequence. 2. **Formula used:** The general term of an arithmetic sequence is given by $$a(n) = a_1 + (n-1)d$$ where $a_1$ is the first term and $d$ is the common difference. 3. **Identify components:** Comparing, $$a(n) = -6 - 4(n - 1) = -6 + (n-1)(-4)$$ So, $a_1 = -6$ and $d = -4$. 4. **Find the first few terms:** - For $n=1$: $$a(1) = -6 - 4(1-1) = -6 - 0 = -6$$ - For $n=2$: $$a(2) = -6 - 4(2-1) = -6 - 4 = -10$$ - For $n=3$: $$a(3) = -6 - 4(3-1) = -6 - 8 = -14$$ 5. **Explanation:** This sequence starts at $-6$ and decreases by $4$ each time. 6. **Summary:** The arithmetic sequence is $-6, -10, -14, -18, \ldots$ with first term $-6$ and common difference $-4$.