1. The problem asks for the first four terms of a sequence starting at 5 where each term is obtained by adding 3 to the previous term. 2. This is an arithmetic sequence where the first term $a_1 = 5$ and the common difference $d = 3$. 3. The formula for the $n$-th term of an arithmetic sequence is: $$a_n = a_1 + (n-1)d$$ 4. Calculate each term: - $a_1 = 5$ - $a_2 = 5 + (2-1) \times 3 = 5 + 3 = 8$ - $a_3 = 5 + (3-1) \times 3 = 5 + 6 = 11$ - $a_4 = 5 + (4-1) \times 3 = 5 + 9 = 14$ 5. Therefore, the first four terms of the sequence are: $$5, 8, 11, 14$$