1. **Stating the problem:** Find the first 4 terms of the arithmetic sequence where the first term is $f(1) = 5$ and the common difference is $d = -\frac{1}{2}$. 2. **Formula used:** The $n$th term of an arithmetic sequence is given by: $$f(n) = f(1) + (n-1)d$$ where $f(1)$ is the first term and $d$ is the common difference. 3. **Calculate the terms:** - For $n=1$: $$f(1) = 5$$ - For $n=2$: $$f(2) = 5 + (2-1)\times \left(-\frac{1}{2}\right) = 5 - \frac{1}{2} = \frac{10}{2} - \frac{1}{2} = \frac{9}{2} = 4.5$$ - For $n=3$: $$f(3) = 5 + (3-1)\times \left(-\frac{1}{2}\right) = 5 - 1 = 4$$ - For $n=4$: $$f(4) = 5 + (4-1)\times \left(-\frac{1}{2}\right) = 5 - \frac{3}{2} = \frac{10}{2} - \frac{3}{2} = \frac{7}{2} = 3.5$$ 4. **Summary:** The first 4 terms of the sequence are: $$5, 4.5, 4, 3.5$$ This sequence decreases by $0.5$ each time, starting from 5.