1. **State the problem:** Savio drives 50 miles to work, thinking his average speed is 40 miles per hour. We need to find the arrival time if this speed is correct. 2. **Use the formula for time:** $$\text{time} = \frac{\text{distance}}{\text{speed}}$$ 3. **Calculate the time taken:** $$\text{time} = \frac{50}{40} = 1.25 \text{ hours}$$ 4. **Convert 1.25 hours to hours and minutes:** $$1.25 \text{ hours} = 1 \text{ hour} + 0.25 \times 60 \text{ minutes} = 1 \text{ hour} + 15 \text{ minutes}$$ 5. **Calculate arrival time:** Savio leaves at 07:30. Adding 1 hour 15 minutes: $$07:30 + 1:15 = 08:45$$ 6. **Answer for part (a):** Savio will arrive at work at 08:45 if his average speed is 40 mph. 7. **Part (b) explanation:** If Savio's actual average speed is greater than 40 mph, the time taken will be less than 1.25 hours. 8. **Effect on arrival time:** He will arrive earlier than 08:45 because higher speed means less travel time.