1. **State the problem:** Maria and Marc both drive approximately 50 miles to work. Maria drives at 60 mph without stops, while Marc drives at 40 mph but stops for 10 minutes. We need to find the difference in their arrival times in minutes if they start at the same time. 2. **Formula for time:** Time = Distance \div Speed 3. **Calculate Maria's travel time:** $$\text{Time}_{Maria} = \frac{50}{60} = \frac{5}{6} \text{ hours}$$ Convert to minutes: $$\frac{5}{6} \times 60 = 50 \text{ minutes}$$ 4. **Calculate Marc's travel time without stop:** $$\text{Time}_{Marc, driving} = \frac{50}{40} = \frac{5}{4} = 1.25 \text{ hours}$$ Convert to minutes: $$1.25 \times 60 = 75 \text{ minutes}$$ 5. **Add Marc's stop time:** $$\text{Time}_{Marc, total} = 75 + 10 = 85 \text{ minutes}$$ 6. **Find difference in arrival times:** $$\text{Difference} = 85 - 50 = 35 \text{ minutes}$$ **Final answer:** Marc arrives 35 minutes later than Maria.