1. Problem: Find the equations of the asymptotes of the function $$f(x) = \frac{3x - 12}{x + 2}$$. 2. To find vertical asymptotes, set the denominator equal to zero and solve for $$x$$: $$x + 2 = 0 \implies x = -2$$. This is a vertical asymptote. 3. To find horizontal or oblique asymptotes, compare degrees of numerator and denominator. Here, both numerator and denominator are degree 1. 4. For rational functions where degrees are equal, horizontal asymptote is the ratio of leading coefficients: $$y = \frac{3}{1} = 3$$. 5. Therefore, the asymptotes are: Vertical asymptote: $$x = -2$$ Horizontal asymptote: $$y = 3$$. Final answer: $$\boxed{\text{Vertical asymptote: } x = -2, \quad \text{Horizontal asymptote: } y = 3}$$