1. **State the problem:** Identify the vertical and horizontal asymptotes of the function $$g(x) = \frac{1}{x - 1} - 5$$. 2. **Vertical asymptote:** Vertical asymptotes occur where the denominator is zero because the function is undefined there. Set the denominator equal to zero: $$x - 1 = 0$$ $$x = 1$$ So, the vertical asymptote is at $$x = 1$$. 3. **Horizontal asymptote:** To find the horizontal asymptote, analyze the behavior of $$g(x)$$ as $$x \to \pm \infty$$. As $$x$$ becomes very large or very small, $$\frac{1}{x - 1} \to 0$$. Therefore, $$g(x) \to 0 - 5 = -5$$ So, the horizontal asymptote is at $$y = -5$$. 4. **Conclusion:** The vertical asymptote is at $$x = 1$$ and the horizontal asymptote is at $$y = -5$$. **Answer:** Option c) Vertical asymptote at $$x = 1$$ and horizontal asymptote at $$y = -5$$.