1. **Problem:** Check if the function $f(x) = \frac{x - 3}{x + 3}$ matches the description: "Vertical asymptote at $x = 3$, horizontal asymptote at $y = 1$, $x$-intercept of $x = -3$." 2. **Step 1: Identify vertical asymptotes.** Vertical asymptotes occur where the denominator is zero and numerator is not zero. Here, denominator $x + 3 = 0$ at $x = -3$. So vertical asymptote is at $x = -3$, not $x = 3$. 3. **Step 2: Identify horizontal asymptote.** For rational functions where degrees of numerator and denominator are equal, horizontal asymptote is ratio of leading coefficients. Both numerator and denominator have degree 1 with leading coefficient 1, so horizontal asymptote is $y = \frac{1}{1} = 1$. This matches the description. 4. **Step 3: Find $x$-intercepts.** Set numerator equal to zero: $x - 3 = 0 \Rightarrow x = 3$. So $x$-intercept is at $x = 3$, not $x = -3$. 5. **Conclusion:** The function has vertical asymptote at $x = -3$, horizontal asymptote at $y = 1$, and $x$-intercept at $x = 3$. The description says vertical asymptote at $x = 3$ and $x$-intercept at $x = -3$, which is incorrect for this function. Therefore, the answer for this function and description is **incorrect**.