1. The problem states that Adam's average marks in subjects A, B, C, D, and E are more than 85. 2. To express the average, we sum the marks of all five subjects and divide by 5. 3. Let the marks in subjects A, B, C, D, and E be $A$, $B$, $C$, $D$, and $E$ respectively. 4. The average is given by the formula $$\frac{A + B + C + D + E}{5}$$. 5. Since the average is more than 85, we write the inequality: $$\frac{A + B + C + D + E}{5} > 85$$. 6. To simplify, multiply both sides by 5: $$A + B + C + D + E > 425$$. 7. This inequality expresses that the total marks in all five subjects must be greater than 425 for the average to be more than 85. Final answer: $$\frac{A + B + C + D + E}{5} > 85$$ or equivalently $$A + B + C + D + E > 425$$.