1. The problem asks for the average rate of change of the function $g(t) = \frac{1}{t}$ between $t=1$ and $t=3$. 2. The formula for the average rate of change of a function $g(t)$ between $t=a$ and $t=b$ is: $$\text{Average Rate of Change} = \frac{g(b) - g(a)}{b - a}$$ 3. Substitute $a=1$ and $b=3$ into the formula: $$\frac{g(3) - g(1)}{3 - 1}$$ 4. Calculate $g(3)$ and $g(1)$: $$g(3) = \frac{1}{3} \approx 0.3333$$ $$g(1) = \frac{1}{1} = 1$$ 5. Substitute these values back: $$\frac{0.3333 - 1}{3 - 1} = \frac{-0.6667}{2}$$ 6. Simplify the fraction: $$\frac{\cancel{-0.6667}}{\cancel{2}} = -0.3333$$ 7. Round to two decimals: $$-0.33$$ Therefore, the average rate of change of $g(t)$ between $t=1$ and $t=3$ is $-0.33$.