1. The problem asks for the axis of symmetry of the curve given by the quadratic equation $$y = 3x^2 - x - 4$$. 2. Recall that the axis of symmetry for a parabola in the form $$y = ax^2 + bx + c$$ is given by the formula: $$x = -\frac{b}{2a}$$ 3. Identify the coefficients from the equation: $$a = 3, \quad b = -1, \quad c = -4$$ 4. Substitute the values into the formula: $$x = -\frac{-1}{2 \times 3} = \frac{1}{6}$$ 5. Therefore, the axis of symmetry is the vertical line: $$x = \frac{1}{6}$$ This line divides the parabola into two mirror-image halves.