1. **Problem Statement:** We are given the x-intercepts of a quadratic function's graph as points (0, -2) and (0, 6). We need to determine if the axis of symmetry is $x = -2$. 2. **Understanding the Problem:** The x-intercepts are points where the graph crosses the x-axis, so their y-values should be zero. However, the given points have x-coordinate 0 and y-values -2 and 6, which means these are actually y-intercepts, not x-intercepts. 3. **Axis of Symmetry for Quadratic Functions:** The axis of symmetry of a parabola $y = ax^2 + bx + c$ is given by the vertical line: $$x = -\frac{b}{2a}$$ It passes through the vertex, which is the midpoint of the x-intercepts. 4. **Given Points Analysis:** Since the points are (0, -2) and (0, 6), both have the same x-coordinate 0, so these are points on the y-axis, not x-intercepts. 5. **Conclusion:** The axis of symmetry cannot be $x = -2$ based on these points because the x-intercepts are not given. The axis of symmetry is the vertical line through the midpoint of the x-intercepts, which cannot be determined from the given points. **Final Answer:** No, it is not true. The axis of symmetry cannot be $x = -2$ based on the given points. It should be determined from the x-intercepts, which are not provided here.