1. The problem is to find the axis of symmetry of the quadratic function $$4x^2 - 2x + 10$$. 2. The formula for the axis of symmetry of a quadratic function $$ax^2 + bx + c$$ is given by: $$x = -\frac{b}{2a}$$ where $a$ and $b$ are coefficients from the quadratic expression. 3. Identify the coefficients from the given quadratic: $$a = 4, \quad b = -2$$ 4. Substitute these values into the formula: $$x = -\frac{-2}{2 \times 4}$$ 5. Simplify the numerator and denominator: $$x = \frac{2}{8}$$ 6. Reduce the fraction by dividing numerator and denominator by 2: $$x = \frac{\cancel{2}^1}{\cancel{8}^4}$$ 7. The reduced fraction is: $$x = \frac{1}{4}$$ 8. Therefore, the axis of symmetry is: $$x = \frac{1}{4}$$ This means the parabola is symmetric about the vertical line $x = \frac{1}{4}$.