1. **Problem Statement:** The vertex of a quadratic function's graph is at the point $(-7,-6)$. We need to determine if the axis of symmetry is $x = -6$. 2. **Recall the axis of symmetry rule:** For a quadratic function in vertex form $y = a(x-h)^2 + k$, the vertex is at $(h,k)$ and the axis of symmetry is the vertical line $x = h$. 3. **Apply the rule:** Given the vertex $(-7,-6)$, the $x$-coordinate of the vertex is $-7$. Therefore, the axis of symmetry must be the vertical line $x = -7$. 4. **Conclusion:** The statement that the axis of symmetry is $x = -6$ is **not true**. The correct axis of symmetry is $x = -7$.