Question: Solving Babylonian Equations
On Babylonian tablet YBC 4652, a problem is given that translates to this equation:
$x + \frac{x}{7} + \frac{1}{11} \left(x + \frac{x}{7}\right) = 60$
What is the solution to the equation?
$x = 48.125$
$x = 52.5$
$x = 60.125$
$x = 77$
1. **State the problem:** Solve the equation $$x + \frac{x}{7} + \frac{1}{11} \left(x + \frac{x}{7}\right) = 60$$ for $x$.
2. **Rewrite the equation:** Let’s simplify the terms inside the parentheses first.
$$x + \frac{x}{7} = \frac{7x}{7} + \frac{x}{7} = \frac{8x}{7}$$
So the equation becomes:
$$x + \frac{x}{7} + \frac{1}{11} \cdot \frac{8x}{7} = 60$$
3. **Express all terms with a common denominator:**
The terms are:
- $x = \frac{7x}{7}$
- $\frac{x}{7}$
- $\frac{1}{11} \cdot \frac{8x}{7} = \frac{8x}{77}$
So the equation is:
$$\frac{7x}{7} + \frac{x}{7} + \frac{8x}{77} = 60$$
4. **Combine the first two terms:**
$$\frac{7x}{7} + \frac{x}{7} = \frac{8x}{7}$$
So now:
$$\frac{8x}{7} + \frac{8x}{77} = 60$$
5. **Find a common denominator for the left side:**
The denominators are $7$ and $77$. Since $77 = 7 \times 11$, the common denominator is $77$.
Rewrite:
$$\frac{8x}{7} = \frac{8x \times 11}{7 \times 11} = \frac{88x}{77}$$
So:
$$\frac{88x}{77} + \frac{8x}{77} = 60$$
6. **Combine the fractions:**
$$\frac{88x + 8x}{77} = \frac{96x}{77} = 60$$
7. **Solve for $x$:**
Multiply both sides by $77$:
$$\cancel{77} \times \frac{96x}{\cancel{77}} = 60 \times 77$$
$$96x = 4620$$
Divide both sides by $96$:
$$x = \frac{4620}{96}$$
Simplify the fraction by dividing numerator and denominator by 12:
$$x = \frac{\cancel{4620}^{385}}{\cancel{96}^{8}}$$
So:
$$x = \frac{385}{8} = 48.125$$
**Final answer:** $x = 48.125$