1. **State the problem:** Bert has some amount of cents. If he had 3 cents more, he would have twice as much as Georgia. If he had 4 cents less, he would have the same amount as Georgia. We need to find how many cents Bert has. 2. **Define variables:** Let $B$ be the number of cents Bert has, and $G$ be the number of cents Georgia has. 3. **Translate the conditions into equations:** - If Bert had 3 cents more, he would have twice as much as Georgia: $$B + 3 = 2G$$ - If Bert had 4 cents less, he would have the same amount as Georgia: $$B - 4 = G$$ 4. **Express $G$ from the second equation:** $$G = B - 4$$ 5. **Substitute $G$ into the first equation:** $$B + 3 = 2(B - 4)$$ 6. **Simplify and solve for $B$:** $$B + 3 = 2B - 8$$ $$3 + 8 = 2B - B$$ $$11 = B$$ 7. **Answer:** Bert has $11$ cents.