1. **Stating the problem:** We need to write an equation for the cost $c$ of hiring a bicycle in pounds in terms of the number of days $d$ it is hired for. 2. **Understanding the problem:** From the given values, the cost for 1 day is 8 pounds and for 2 days is 10 pounds. We want to find a formula that relates $c$ and $d$. 3. **Formulating the equation:** Assuming the cost has a fixed base charge plus a daily rate, the equation can be written as: $$c = m d + b$$ where $m$ is the cost per day and $b$ is the fixed base cost. 4. **Using the given data to find $m$ and $b$:** For $d=1$, $c=8$: $$8 = m \times 1 + b$$ For $d=2$, $c=10$: $$10 = m \times 2 + b$$ 5. **Solving the system:** Subtract the first equation from the second: $$10 - 8 = 2m + b - (m + b)$$ $$2 = m$$ So, the cost per day $m$ is 2 pounds. 6. **Find $b$ using $m=2$ in the first equation:** $$8 = 2 \times 1 + b$$ $$b = 8 - 2 = 6$$ 7. **Final equation:** $$c = 2d + 6$$ 8. **Complete the table:** - For $d=1$: $c = 2(1) + 6 = 8$ (already given) - For $d=2$: $c = 2(2) + 6 = 10$ (already given) - For $d=3$: $c = 2(3) + 6 = 12$ So, the values replacing A, B, and C are: - A = 8 - B = 10 - C = 12 **Answer:** The equation is $$c = 2d + 6$$ and the completed table values are 8, 10, and 12 for days 1, 2, and 3 respectively.