1. The problem is to simplify and evaluate the expression $\left(\sqrt{3} + 1.2\right)^2$. 2. The formula for squaring a binomial is $$(a+b)^2 = a^2 + 2ab + b^2$$ where $a = \sqrt{3}$ and $b = 1.2$. 3. Calculate each term: - $a^2 = (\sqrt{3})^2 = 3$ - $b^2 = (1.2)^2 = 1.44$ - $2ab = 2 \times \sqrt{3} \times 1.2 = 2.4\sqrt{3}$ 4. Substitute back: $$\left(\sqrt{3} + 1.2\right)^2 = 3 + 2.4\sqrt{3} + 1.44$$ 5. This is the simplified exact form. For an approximate decimal value, use $\sqrt{3} \approx 1.732$: $$2.4 \times 1.732 = 4.1568$$ 6. Add all terms: $$3 + 4.1568 + 1.44 = 8.5968$$ 7. Final answer: $$\boxed{8.5968}$$ Your solution contains some incorrect steps and unclear operations such as mixing fractions and unrelated numbers. The correct approach is to use the binomial square formula as shown above.