1. **State the problem:** We have the formula for the number of blades of grass on a fertilized lawn as $$B = 48l \pm 2$$ where $B$ is the number of blades and $l$ is the area of the lawn in square inches. 2. **Determine the domain:** The problem states the area $l$ is between 14 in² and 22 in², so the domain is $$14 \leq l \leq 22$$. 3. **Calculate the range:** Using the formula, calculate the minimum and maximum number of blades for the given domain. - Minimum blades when $l=14$: $$B_{min} = 48 \times 14 - 2 = 672 - 2 = 670$$ - Maximum blades when $l=22$: $$B_{max} = 48 \times 22 + 2 = 1056 + 2 = 1058$$ 4. **Express the range:** The range of $B$ is therefore: $$670 \leq B \leq 1058$$ 5. **Summary:** - Domain: $$14 \leq l \leq 22$$ - Range: $$670 \leq B \leq 1058$$ This means for lawn areas between 14 and 22 square inches, the number of blades of grass will be between 670 and 1058 blades, accounting for the uncertainty of ±2 blades.