Subjects algebra

Books Ownership 9Ef589

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1. **State the problem:** Mason owns 48 books in total. Hanna owns 6 times as many non-fiction books as Mason. We need to find how many books Hanna owns in total. 2. **Analyze Mason's books:** Mason's pie chart shows a 195° orange sector for fiction and the rest for non-fiction. Since a full circle is 360°, Mason's non-fiction sector is $$360^\circ - 195^\circ = 165^\circ$$. 3. **Calculate Mason's non-fiction books:** The fraction of Mason's books that are non-fiction is $$\frac{165}{360}$$. Number of Mason's non-fiction books: $$48 \times \frac{165}{360} = 48 \times \frac{11}{24} = \cancel{48}^2 \times \frac{11}{\cancel{24}^1} = 2 \times 11 = 22$$ 4. **Calculate Hanna's non-fiction books:** Hanna owns 6 times as many non-fiction books as Mason, so: $$6 \times 22 = 132$$ 5. **Analyze Hanna's books:** Hanna's pie chart shows a 120° orange sector for fiction and the rest for non-fiction. The non-fiction sector is: $$360^\circ - 120^\circ = 240^\circ$$ 6. **Calculate total books Hanna owns:** Let total books Hanna owns be $T$. The fraction of non-fiction books Hanna owns is $$\frac{240}{360} = \frac{2}{3}$$. Since non-fiction books are 132, we have: $$\frac{2}{3} T = 132$$ Divide both sides by $\frac{2}{3}$: $$T = 132 \div \frac{2}{3} = 132 \times \frac{3}{2} = \cancel{132}^ {66} \times \frac{3}{\cancel{2}^1} = 66 \times 3 = 198$$ **Final answer:** Hanna owns **198** books in total.