1. **State the problem:** We have a total of 432 students in a school with a ratio of boys to girls as 6:4. We need to find how many more boys than girls are in the school. 2. **Understand the ratio:** The ratio 6:4 means for every 6 boys, there are 4 girls. The total parts in the ratio are $6 + 4 = 10$ parts. 3. **Calculate the value of one part:** Since the total number of students is 432, each part represents $$\frac{432}{10} = 43.2$$ students. 4. **Find the number of boys:** Number of boys = $6 \times 43.2 = 259.2$ (since number of students must be whole, we consider exact ratio parts for calculation). 5. **Find the number of girls:** Number of girls = $4 \times 43.2 = 172.8$. 6. **Calculate how many more boys than girls:** Difference = $259.2 - 172.8 = 86.4$. Since the number of students must be whole numbers, the ratio implies the actual numbers are multiples of 6 and 4 respectively, so the difference is exactly $6 - 4 = 2$ parts, each part being 43.2 students. Therefore, the number of more boys than girls is $$2 \times 43.2 = 86.4$$, which rounds to 86 students. **Final answer:** There are 86 more boys than girls in the school.