1. **State the problem:** We have two drama groups. The first group has 36 boys and 48 girls. The second group has boys making up $\frac{3}{7}$ of the students, and the rest are girls. Ann claims the ratio of boys to girls is the same in both groups. We need to check if Ann is correct. 2. **Formula and rules:** The ratio of boys to girls is given by $\frac{\text{number of boys}}{\text{number of girls}}$. 3. **Calculate the ratio for the first group:** $$\text{Ratio}_1 = \frac{36}{48} = \frac{3}{4}$$ 4. **Calculate the ratio for the second group:** Let the total number of students in the second group be $N$. Number of boys = $\frac{3}{7}N$. Number of girls = $N - \frac{3}{7}N = \frac{4}{7}N$. Ratio of boys to girls in the second group: $$\text{Ratio}_2 = \frac{\frac{3}{7}N}{\frac{4}{7}N} = \frac{3}{7}N \times \frac{7}{4N} = \frac{3}{4}$$ 5. **Compare the ratios:** $$\text{Ratio}_1 = \frac{3}{4} \quad \text{and} \quad \text{Ratio}_2 = \frac{3}{4}$$ Since both ratios are equal, Ann is correct. **Final answer:** Yes, Ann is correct. The ratio of boys to girls is the same for both groups, $\frac{3}{4}$.