Subjects algebra

Break Fraction 1A399E

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1. **State the problem:** Jada works a 5-hour shift (300 minutes) and takes a 15-minute break. We want to find what fraction and percentage of her work shift the break represents. 2. **Find the fraction of the break over the total shift:** $$\frac{15}{300}$$ 3. **Simplify the fraction:** $$\frac{15}{300} = \frac{\cancel{15}^1}{\cancel{300}^{20}} = \frac{1}{20}$$ This means the break is \(\frac{1}{20}\) of the total shift. 4. **Find an equivalent fraction with denominator 100:** We want to find \(x\) such that: $$\frac{15}{300} = \frac{x}{100}$$ Cross-multiply: $$15 \times 100 = 300 \times x$$ $$1500 = 300x$$ Divide both sides by 300: $$\frac{1500}{\cancel{300}} = \frac{300x}{\cancel{300}} \Rightarrow 5 = x$$ So the equivalent fraction is: $$\frac{5}{100}$$ 5. **Interpretation:** The break is \(\frac{1}{20}\) or \(\frac{5}{100}\) of the shift, which is 5%.